The power dissipated in the circuit shown in | vedclass

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(A) The equivalent resistance $R_{eq}$ of the two resistors $R$ and $5 \, \Omega$ connected in parallel is given by:$R_{eq} = \frac{R 	imes 5}{R + 5}

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$10$

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(A) The equivalent resistance $R_{eq}$ of the two resistors $R$ and $5 \, \Omega$ connected in parallel is given by:$R_{eq} = \frac{R 	imes 5}{R + 5}$The power dissipated in the circuit is given by the formula:$P = \frac{V^2}{R_{eq}}$Given $P = 30 \, W$ and $V = 10 \, V$,we substitute these values into the formula:$30 = \frac{10^2}{\left(\frac{5R}{R + 5}ight)}$$30 = \frac{100(R + 5)}{5R}$$30 = \frac{20(R + 5)}{R}$$30R = 20R + 100$$10R = 100$$R = 10 \, \Omega$

The power dissipated in the circuit shown in the figure is $30 \, W$. The value of $R$ is ............. $\Omega$.

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